7x+2[3(1-x)-2(1+x)]=14

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Solution for 7x+2[3(1-x)-2(1+x)]=14 equation:


Simplifying
7x + 2[3(1 + -1x) + -2(1 + x)] = 14
7x + 2[(1 * 3 + -1x * 3) + -2(1 + x)] = 14
7x + 2[(3 + -3x) + -2(1 + x)] = 14
7x + 2[3 + -3x + (1 * -2 + x * -2)] = 14
7x + 2[3 + -3x + (-2 + -2x)] = 14

Reorder the terms:
7x + 2[3 + -2 + -3x + -2x] = 14

Combine like terms: 3 + -2 = 1
7x + 2[1 + -3x + -2x] = 14

Combine like terms: -3x + -2x = -5x
7x + 2[1 + -5x] = 14
7x + [1 * 2 + -5x * 2] = 14
7x + [2 + -10x] = 14

Reorder the terms:
2 + 7x + -10x = 14

Combine like terms: 7x + -10x = -3x
2 + -3x = 14

Solving
2 + -3x = 14

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3x = 14 + -2

Combine like terms: 2 + -2 = 0
0 + -3x = 14 + -2
-3x = 14 + -2

Combine like terms: 14 + -2 = 12
-3x = 12

Divide each side by '-3'.
x = -4

Simplifying
x = -4

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